Machinedesign 2114 Latest Developments Equ 1 0 0

Latest developments in voice coil actuators

Oct. 1, 2000
Need smooth motion, high speed and acceleration, or tight servo control? Voice coil actuators, providing rotary or linear motion, may be the solution you need. Here is a look at choosing the right one for your application.

Voice coil actuators are direct-drive electric motors that provide limited linear or rotary motion. They are often used in applications requiring proportional and tight servo control, such as mirror and lens positioning in optical systems, high-accuracy machine tool positioning, precision valve control in medical and industrial devices, and linear drives for cryogenic coolers and other pumps.

These non-commutated actuators use a permanent-magnet field assembly with a coil winding to produce a force proportional to the current applied to the coil. Both linear and rotary versions meet the acceleration, frequency actuation, and linear force or torque-versus-stroke output requirements needed in many linear and rotary motion applications. Some of the linear versions, Figure 1, provide continuous force (stall) from 1.15 to 9.7 lb, with a peak force for 10 sec from 2.5 to 32.5 lb. Some rotary versions provide continuous torque (stall) from 4.05 to 480 ozin, with 10-sec peak torque from 11 to 1,536 oz-in.

A linear voice coil actuator consists of a two-terminal tubular coil of wire in a radially oriented dc magnetic field, Figure 2. Permanent magnets embedded on the inside diameter of a ferromagnetic cylinder produce a constant field. The side of the magnets that faces the ferromagnetic cylinder has the same polarity as the cylinder. The opposite side of the magnets facing the coil has the opposite polarity. Completing the magnetic circuit is an inner core of ferromagnetic material along the axial centerline of the coil that is joined at one end to the permanent magnet assembly.

The actuator is a single-phase device. It operates using the cross product of a magnetic field and a current flow through the coil winding. Applying voltage across the two coil leads generates a current in the winding. This current produces a proportional force on the coil, causing the coil to move axially along the air gap. The direction of the current flow in the wire determines the direction of movement. The speed of actuation depends on the magnitude of the current flowing through and the voltage applied to the coil.

From a straight line to a curve

If you “flatten” a linear voice coil actuator, Figure 2, from a round tube to a flat tube, then bend the two ends to form a planar arc, you will have a rotary voice coil actuator, Figure 3A and 3B. Rotary voice coil actuators generate force identical to their linear counterparts. However, the ratings are in units of torque, instead of force, because force is generated along the circumference of an arc.

Material composition

Both types of actuators are available in several materials, depending on required system performance, operating environment, manufacturing considerations, and cost. Typically, the coil is wound with copper or aluminum-magnet wire coated with a thin polymer film for electrical insulation.

The most common permanent magnet materials are hard-magnetic ferrites, Neodymium Iron Boron, and Samarium Cobalt. The steel flux return, or “backiron” steel, can be any high permeability ferromagnetic material, and need not be laminated. The fasteners and bonding agents must be able to survive the required operating environment.

Control

In precise servo control applications, voice coil actuators require feedback for closed-loop control. Many position, velocity, and force transducers can function as feedback devices. Most common are optical encoders, contact and magneto-resistive potentiometers, LVDT’s, and load cells.

The actuator’s power supply must have sufficient current to meet an application’s force requirements. It must have a high enough voltage rating to overcome the back EMF at maximum coil velocity and the resistive and inductive voltage drops across the winding.

The coil resistance (Ohms) and force sensitivity (Newtons/Ampere) of these actuators can be impedance matched to most dc power supplies. Common amplifiers include H-bridge and PWM types.

Mechanical systems

Voice coil actuators are usually sold as a set consisting of the magnet and coil assemblies. The minimum air gap clearance between these assemblies is 0.010- 0.015 inches; sometimes more if required by the application. The user must provide a guidance system for full range of motion and to prevent the coil winding from rubbing against or crashing into the magnet assembly. In most cases, the load is connected to the coil assembly because the coil has a lower mass (often by an order of magnitude) than the field assembly. In cases where the load is sensitive to applied heat, it can be connected to the magnet assembly.

Continue on page 2

The preferred guiding means for the linear version consists of linear bearings or bushings combined with steel shafts, though flexures are often used in shortstroke applications. If needed, actuator manufacturers can make shaft-bushing combinations an integral part of the actuator. It is important to keep the friction levels of the guidance system low to ensure the smooth response characteristics of these actuators. Rotary voice coil actuators typically use shaft-ball bearing guidance systems identical to those of conventional electric motors.

Choosing a rotary voice coil actuator

Rotary voice coil actuators are frequently used in gimbal assemblies for flight hardware systems. These applications often require low weight and a small “footprint.” Rotary voice coil actuators offer these features plus low inertia and high torque output over a limited angle of operation.

Several calculations are necessary to choose the right actuator. In this example, Figure 4, the engineering parameters are:
• Voltage available, 12 Vdc.
• Total angular travel of inner axis is 40 deg; outer axis is 20 deg.
• Move time of inner axis is 32 msec; outer axis is 140 msec.
• Load and friction torque of inner axis is 3 oz-in.; of outer axis, 9 oz-in.
• Assume a polished aluminum mirror weight of 3.4 oz. Dimensions of the mirror are ¼ by 3 by 3 in. with a slight curvature.
• Mirror inertia about the inner axis of rotation is 0.0066 oz-in.-sec2
• Inner axis aluminum support weight is 17 oz.

Four series of calculations are needed: Inner axis acceleration torque, inner axis winding verification, outer axis (or complete assembly) acceleration torque, and outer axis winding verification. Only the inner axis acceleration torque will be described to illustrate the process.

Inner axis acceleration torque

The mirror load inertia is known, but actuator coil inertia and acceleration rate are not. Determine the acceleration rate for the angular displacement requirement during a triangular move, Figure 5, using equations 1 and 2:

In a triangular move profile, though, acceleration occurs during the first half of the move, or in this case, in 16 msec. a = acceleration rate = (44 Rad/sec)/(16 msec) = 2750 Rad/sec2.

Ignoring coil inertia for the time being, determine the torque required to accelerate the mirror:

This torque must be available for deceleration, too. In addition, the continuous duty operation calls for an actuator with a continuous torque rating of at least the required 18 oz-in.

To check the effect of coil inertia on the overall torque requirement: assume an actuator with a coil inertia of approximately 8.5 X 10-5 oz-in.-sec2 about an axis perpendicular to the plane of motion, through the center of mass in the coil. In this application, the coil will not rotate about its own center of mass. Instead, it will rotate about an axis parallel to its own axis and two inches away. Equation 4 determines the inertia of the coil, relative to the axis of rotation — the rotational axis of the mirror — using the mass of the body, m, and the distance, d, between the two parallel axes.

The total acceleration torque requirement is:

a value higher than the 18 oz-in. initially calculated.

Continue on page 3

The total peak torque, Tp, requirement is therefore the total acceleration torque, Ta plus the load and friction torque from the engineering parameters, 3 oz-in., which equals 34 oz-in. Using the recommended 20% safety margin, this example calls for an actuator with a peak and continuous torque rating of:

Peak = 1.2 (34 oz-in.) = 41 oz-in.

Continuous = 1.2 (31 oz-in.) = 37 oz-in.

Calculating the outer axis acceleration torque follows a similar procedure.

Choosing a linear voice coil actuator for an X/Y stage application

A designer wants to sinusoidally oscillate a 1.0 lb load over the maximum attainable frequency for two linear displacements:

D1 = ±.050 in. and

D2 = ±.450 in.

The customer’s envelope dimensions are a 2.75-in. maximum outer diam and a 5.00-in. maximum length with the coil fully extended.

Customer requirements and specifications:
• Power supply voltage = open
• Power supply current = open
• Wl = Load mass = 1.0 lb
• Duty cycle = 10%
• Maximum OD = 2.75 in.
• Maximum length = 5.00 in. (fully extended)
• Stroke, case 1, (D1) = ± .050 in. = .100 in. =

case 2, (D2) = 6 .450 in. = .900 in.

• Maximum frequency = unknown

The chosen linear voice coil actuator meets the designer’s envelope dimensions and stroke requirements, while providing high force.

• Fp = Peak force = 60 lb
• Fcs = Continuous stall force = 19.4 lb
• KF = Force constant = 4.8 lb/A
• R = Coil resistance = 2.4 ohms
• Stroke = ±.500 in.
• KB = Back EMF constant = 6.51 V/(ft/s)
• Wc = Coil assembly mass = 1.20 lb
• Vm = Coil thermal resistance = 2.2
C/W = ϑ

Determining the moving mass and acceleration:

Moving mass:

Acceleration:

Determining the maximum frequency and velocity:

Case 1: D1 = .100 in., G = 27.3 G

Frequency:

Velocity:

Continue on page 4

Case 2: D2 = .900 in., G = 27.3G

Frequency:

Velocity:

To determine current, voltage, and power:

Peak current:

The current will assume a sinusoidal waveform, such that:

The maximum voltage required is composed of three components: resistive drop across the coil, inductive drop across the coil, and the generated back EMF:

Also calculate the increase in coil resistance due to heating, RH. Assume a worst case coil temperature of 155 C and a 25 C ambient:

Case 1: velocity = 1.91 ft/sec

L(di/dt) = 15 V (conservative estimate)

Case 2: velocity = 5.65 ft/sec

L(di/dt) = 5 V (conservative estimate)

The amount of power dissipated in the coil is from I22R heating only: The final coil temperature should be less than the 155 C maximum rating for the winding:

Anthony Morcos is senior magnetics engineer, BEI Sensors & Systems Co., Kimco Magnetics Div.

Sponsored Recommendations

Precision Motion Control for Robotics Systems

April 8, 2024
Learn more about Precision Motion Control for your Robotic Systems through Harmonic Drive's latest Webinar!

KNF Pumps Revolutionize Desert Dust Tracking

April 3, 2024
The Sahara Desert is one of the biggest sources of dust worldwide. KNF air sampling pumps help tracing this particulate matter air pollution.

Introducing the Mass Flow Rate Calculator

April 3, 2024
The KNF Mass Flow Rate Calculator makes it easy to convert volume flow rate to mass flow rate. Simply enter the volume flow and the gas or gas mixture.

Explore KNF's Cutting-Edge DC-BI Pump Drive Technology

April 3, 2024
With six new DC-BI pump series, KNF launches an entirely new pump drive technology relying on advanced BLDC motors and achieving unprecedented advantages.

Voice your opinion!

To join the conversation, and become an exclusive member of Machine Design, create an account today!